5a^2+50a-50=0

Solution for 5a^2+50a-50=0 equation:

5a^2+50a-50=0

a = 5; b = 50; c = -50;
Δ = b2-4ac
Δ = 502-4·5·(-50)
Δ = 3500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3500}=\sqrt{100*35}=\sqrt{100}*\sqrt{35}=10\sqrt{35}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{35}}{2*5}=\frac{-50-10\sqrt{35}}{10}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{35}}{2*5}=\frac{-50+10\sqrt{35}}{10}
$